Question

What is the solution set of `x^2- 3x= 10`?

Answer 1

`x=5`
or `x=-2`

Explanation:

`x^2-3x=10`

subtract 10 from the right hand side so the equation =0
`x^2-3x-10=0`

factorise the equation by working out what adds to make -3 and multiplies to make -10
in this case it would be -5 and 2
`(x-5)(x+2)=0`

place each bracket = 0
`x-5=0`
`x+2=0`

then work out x
`x=5`
`x=-2`