What is the solution to the function using Chain Rule?

F(t)= #e^(2tsin(2t)#

1 Answer
Martin C.
Feb 26, 2018

#F'(t)=(4tcos(2t)+2sin(2t))e^(2tsin(2t))#

Explanation:

#F'(t)=(e^(2tsin(2t)))d/dt#
#v=2tsin(2t)#
#(e^v)d/dt=v'*e^v#
#v'=ad/dtb+bd/dta#
#a=2t#
#a'=2#
#b=sin(2t)#
#b'=2cos(2t)#
#v'=4tcos(2t)+2sin(2t)#
#F'(t)=(4tcos(2t)+2sin(2t))e^(2tsin(2t))#

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