What is the specific heat capacity of substance if #2.41times10^4# #J# are needed to change the temperature of #105.0# #g# of it from #25.00°C# to #250.0°C#?

1 Answer
Feb 25, 2017

Answer:

The specific heat capacity of the substance is #1.02"J"/("g"*^@"C")#.

Explanation:

The equation to use is #color(red)(Q=mcDeltat)#, where #Q# is the amount of energy gained or lost, #m# is mass in grams, #c# is specific heat capacity, and #color(blue)(Deltat# is the change in temperature, #color(blue)(t_f-t_i#.

To answer this question, rearrange the equation to isolate specific heat capacity. Substitute the known values into the equation and solve.

#c=Q/(mDeltat)#

#c=(2.41xx10^4"J")/(105.0"g"xx(250.0^@"C"-25.0^@"C"))#

#c=(2.41xx10^4"J")/(105.0"g"xx225.0^@"C")#

#c=1.02"J"/("g"*^@"C")#