# What is the specific heat capacity of substance if 2.41times10^4 J are needed to change the temperature of 105.0 g of it from 25.00°C to 250.0°C?

Feb 25, 2017

The specific heat capacity of the substance is 1.02"J"/("g"*^@"C").

#### Explanation:

The equation to use is $\textcolor{red}{Q = m c \Delta t}$, where $Q$ is the amount of energy gained or lost, $m$ is mass in grams, $c$ is specific heat capacity, and color(blue)(Deltat is the change in temperature, color(blue)(t_f-t_i.

To answer this question, rearrange the equation to isolate specific heat capacity. Substitute the known values into the equation and solve.

$c = \frac{Q}{m \Delta t}$

c=(2.41xx10^4"J")/(105.0"g"xx(250.0^@"C"-25.0^@"C"))

$c = \left(2.41 \times {10}^{4} \text{J")/(105.0"g"xx225.0^@"C}\right)$

c=1.02"J"/("g"*^@"C")