# What is the specific heat of a material if a 6.0 g sample absorbs 50 J when it is heated from 30°C to 50°C?

Nov 9, 2015

$C s$= 0.4167$\frac{J}{g C}$

#### Explanation:

Use the equation $q = m {C}_{s} \Delta T$

You are given the $q$ in the form of J. You are given the mass in grams and also the initial and final temperature. $\Delta$T = ${T}_{f}$-${T}_{i}$.

If you plug in the known variables the equation will look like:
$50 J$=$6 g$$\left({C}_{s}\right)$$20 C$

At this point you just solve for ${C}_{s}$ using some algebra.

$50 J$/$\left(6 g\right)$$\left(20 C\right)$

It is really helpful to keep units in the equation when solving. Let the units lead the way in solving thermochemistry problems.