What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15° C?

Mar 5, 2016

The specific heat capacity of the substance is $\text{0.33 cal·g"^"-1""°C"^"-1}$.

Explanation:

The amount of heat required is determined from the formula

q = mcΔT,

where

• $q$ is the amount of heat transferred
• $m$ is the mass of the substance
• $c$ is the specific heat capacity of the substance
• ΔT is the change in temperature

$q = \text{1560 cal}$
$m = \text{312 g}$
ΔT = "15 °C"

c = q/(mΔT) = "1560 cal"/("312 g × 15 °C") = "0.33 cal·g"^"-1""°C"^"-1"