# What is the speed of an object that travels from (4,-7,1)  to (-1,9,3)  over 6 s?

Jan 29, 2016

Velocity $v = 2.81 m {s}^{-} 1$

#### Explanation:

Well, first we need to find the displacement of the object.

The initial point is $\left(4 , - 7 , 1\right)$ and the final point is $\left(- 1 , 9 , 3\right)$
So, to find the least displacement, we use the formula
$s = \setminus \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}}$

Taking the initial points as that of ${x}_{1}$ and so on, with the final points as the other, we find $s = 16.88 m$

Now, the total time taken for this transit is $6 s$
So, the velocity of the object in this transit would be $\frac{16.88}{6} = 2.81 m {s}^{-} 1$