# What is the speed of an object that travels from ( -5 , 2, 3 )  to (6 , 0, 7 )  over 4 s?

Feb 21, 2016

$v \cong 2 , 97 \frac{m}{s}$

#### Explanation:

$\text{Distance between two point is equal to :}$
$s = \sqrt{\Delta {x}^{2} + \Delta {y}^{2} + \Delta {z}^{2}}$
s=sqrt(11²+(-2)^2+4^2)
$s = \sqrt{121 + 4 + 16}$
$s = \sqrt{141} = 11 , 87 m$
$v = \frac{s}{t}$
$v = \frac{11 , 87}{4}$
$v \cong 2 , 97 \frac{m}{s}$