What is the speed of an object that travels from #( 6, -3, 1) # to #(-1, -2, 7 ) # over #4 s#?

1 Answer
Jun 5, 2017

Answer:

The speed is #=2.32ms^-1#

Explanation:

The distance between the points #A=(x_A,y_A,z_A)# and the point #B=(x_B,y_B,z_B)# is

#AB=sqrt((x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2)#

#dt= sqrt((-1-6)^2+(-2+3)^2+(7-1)^2)#

#=sqrt(7^2+1^2+6^2)#

#=sqrt(49+1+36)#

#=sqrt86#

#=9.27m#

The speed is

#v=d/t=9.27/4=2.32ms^-1#