What is the square root 48 - 8 square root 12 - 4 square root 27?

1 Answer
Jul 19, 2015

Answer:

You try to get 'squares out of the root'

Explanation:

#48=16*3=4^2*3# so:
#sqrt48=sqrt(16*3)=sqrt(4^2)*sqrt3=4sqrt3#

Same goes for:
#12=4*3=2^2*3# so #sqrt12=2sqrt3#

#27=9*3=3^2*3# so #sqrt27=3sqrt3#

The original question then changes into:

#=4sqrt3-8*2sqrt3-4*3sqrt3#

#=(4-16-12)*sqrt3=-24sqrt3#