# What is the square root of 98?

Oct 24, 2015

$\sqrt{98} = 7 \sqrt{2} \approx 9.89949493661166534161$

#### Explanation:

If $a , b \ge 0$ then $\sqrt{a b} = \sqrt{a} \sqrt{b}$

So $\sqrt{98} = \sqrt{{7}^{2} \cdot 2} = \sqrt{{7}^{2}} \sqrt{2} = 7 \sqrt{2}$

$\sqrt{98}$ is irrational, so its decimal representation neither terminates nor repeats.

It can be expressed as a repeating continued fraction:

sqrt(98) = [9;bar(1,8,1,18)] = 9+1/(1+1/(8+1/(1+1/(18+...))))