# What is the standard form for y = 4(x - 2)^2 - 1?

Apr 8, 2018

$y = 4 {x}^{2} - 14 x + 15$

#### Explanation:

$y = 4 {\left(x - 2\right)}^{2} - 1$

$y = 4 \left({x}^{2} - 4 x + 4\right) - 1$ expand binomial product

$y = 4 {x}^{2} - 14 x + 16 - 1$ expand brackets

$y = 4 {x}^{2} - 14 x + 15$ simplify