What is the standard form for $y = 4 {(x - 2)}^{2} - 1$ $y = 4(x - 2)^2 - 1$ ?

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Answer 1 · 2018-04-08T07:55:32

$y = 4 x^{2} - 14 x + 15$ $y=4x^2-14x+15$

$y = 4 {(x - 2)}^{2} - 1$ $y=4(x-2)^2-1$

$y = 4 (x^{2} - 4 x + 4) - 1$ $y=4(x^2-4x+4)-1$ expand binomial product

$y = 4 x^{2} - 14 x + 16 - 1$ $y=4x^2-14x+16-1$ expand brackets

$y = 4 x^{2} - 14 x + 15$ $y=4x^2-14x+15$ simplify

What is the standard form for y=4(x−2)2−1y = 4(x - 2)^2 - 1?