What is the standard form of $(2 x - y) (2 y - 3)$ $(2x-y)(2y-3)$ ?

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What is the standard form of $(2 x - y) (2 y - 3)$ $(2x-y)(2y-3)$ ?

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Answer 1 · 2017-04-19T14:18:03

$2 y^{2} - 3 y + 4 x y$ $2y^2-3y+4xy$

Explanation:

$(2 x - y) (2 y - 3)$ $(2x-y)(2y-3)$
Let's use the distributive property:
$(2 x \cdot 2 y) (- 3 \cdot 2 x) + (- y \cdot 2 y) + (- y \cdot - 3)$ $(2x*2y)(-3*2x)+(-y*2y)+(-y*-3)$
simplify
$4 x y - 6 y - 2 y^{2} + 3 y$ $4xy-6y-2y^2+3y$
$2 y^{2} - 3 y + 4 x y$ $2y^2-3y+4xy$

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What is the standard form of $(2 x - y) (2 y - 3)$ $(2x-y)(2y-3)$ ?

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What is the standard form of (2x−y)(2y−3) (2x-y)(2y-3) ?

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Explanation:

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What is the standard form of $(2 x - y) (2 y - 3)$ $(2x-y)(2y-3)$ ?