What is the standard form of 2xy (x^2 -3y +2) 2xy(x23y+2)?

1 Answer
Dec 7, 2017

In standard form the expression is writtens 2x^3y + 4xy - 6xy^22x3y+4xy6xy2

Explanation:

In standard form, the powers of xx decrease from one term to the next, but the powers of yy increase -- as far as possible.

Write this polynomial in standard form
2 x y (x^2 − 3 y + 2 )2xy(x23y+2)

1) Clear the parentheses by distributing the 2xy2xy to every term inside the parentheses

2x^3y - 6xy^2 + 4xy2x3y6xy2+4xy

2) Rearrange the terms into standard order.
Bring the signs of the terms with you when you rearrange them.

2x^3y + 4xy - 6xy^22x3y+4xy6xy2 larr answer

The powers of xx decreased from x^3x3 to x^1x1 to another x^1.x1.
Meanwhile, the powers of yy went up from y^1y1 to y^1y1 (again) to y^2y2

Answer:

The expression in standard form is

2x^3y + 4xy - 6xy^22x3y+4xy6xy2