# What is the standard form of f(x)=8(x+1)^2-2x-2 ?

$f \left(x\right) = 8 {x}^{2} + 14 x + 6$
$f \left(x\right) = 8 \left({x}^{2} + 2 x + 1\right) - 2 x - 2$
$f \left(x\right) = 8 {x}^{2} + 16 x + 8 - 2 x - 2$
$f \left(x\right) = 8 {x}^{2} + 14 x + 6$