Question

What is the standard form of `f(x)=8(x+1)^2-(3x+3)^2`?

Answer 1

`f(x)=-x^2-2x-1`

Explanation:

To rewrite the function in standard form, expand the brackets:

`f(x)=8(x+1)^2-(3x+3)^2`

`f(x)=8(x+1)(x+1)-(3x+3)(3x+3)`

`f(x)=8(x^2+2x+1)-(9x^2+18x+9)`

`f(x)=8x^2+16x+8-9x^2-18x-9`

`f(x)=8x^2-9x^2+16x-18x+8-9`

`f(x)=-x^2-2x-1`