What is the standard form of f(x)=8(x+1)^2-(3x+3)^2 f(x)=8(x+1)2−(3x+3)2?

1 Answer
Johnson Z.
Dec 22, 2015

f(x)=-x^2-2x-1f(x)=−x2−2x−1

Explanation:

To rewrite the function in standard form, expand the brackets:

f(x)=8(x+1)^2-(3x+3)^2f(x)=8(x+1)2−(3x+3)2

f(x)=8(x+1)(x+1)-(3x+3)(3x+3)f(x)=8(x+1)(x+1)−(3x+3)(3x+3)

f(x)=8(x^2+2x+1)-(9x^2+18x+9)f(x)=8(x2+2x+1)−(9x2+18x+9)

f(x)=8x^2+16x+8-9x^2-18x-9f(x)=8x2+16x+8−9x2−18x−9

f(x)=8x^2-9x^2+16x-18x+8-9f(x)=8x2−9x2+16x−18x+8−9

f(x)=-x^2-2x-1f(x)=−x2−2x−1

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