# What is the standard form of the equation of this parabola #y^2+6y+x+10=0#?

##### 1 Answer

Mar 17, 2017

$$ y = \sqrt(-x-10+9) -3 $$

#### Explanation:

$$ (y+3)^2 = y^2+9+6y $$

$$ y^2+6y = (y+3)^2-9 $$

$$ y^2+6y + x + 10 = (y+3)^2-9 + x + 10 = 0 $$

$$ (y+3)^2 = -x-10+9 $$

$$ y+3 = \sqrt(-x-10+9) $$

$$ y = \sqrt(-x-10+9) -3 $$