What is the standard form of #y= (1/5x^2-1/12)(1/3x+3/8) #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Tony B Mar 12, 2016 #y=1/15x^3+3/40x^2-1/36x-3/96# Explanation: Given:#color(brown)(y=color(blue)((1/5x^2-1/12)) (1/3x+3/8)# #color(brown)(y=color(blue)(1/5x^2) (1/3x+3/8)+color(blue)((-1/12))(1/3x+3/8))# #y=(1/15x^3 +3/40 x^2)+(-1/36x-3/96)# #y=1/15x^3+3/40x^2-1/36x-3/96# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1532 views around the world You can reuse this answer Creative Commons License