What is the standard form of $y = {(12 x - 2)}^{2} + 11 x$ $y= (12x-2)^2 + 11x$ ?

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What is the standard form of $y = {(12 x - 2)}^{2} + 11 x$ $y= (12x-2)^2 + 11x$ ?

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Answer 1 · 2016-01-22T08:33:49

$y = 144 x^{2} - 37 x + 4$ $y= 144x^2 - 37x +4$

Explanation:

To put a polynomial into standard form, multiply out to get rid of the brackets, then group like items and put in descending order of powers.
$y = {(12 x - 2)}^{2} + 11 x$ $y=(12x-2)^2 +11x$
$y = 144 x^{2} - 48 x + 4 + 11 x$ $y=144x^2 -48x +4 +11x$

$y = 144 x^{2} - 37 x + 4$ $y= 144x^2 - 37x +4$

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What is the standard form of $y = {(12 x - 2)}^{2} + 11 x$ $y= (12x-2)^2 + 11x$ ?

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What is the standard form of y= (12x-2)^2 + 11xy=(12x−2)2+11xy= (12x-2)^2 + 11x?

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What is the standard form of $y = {(12 x - 2)}^{2} + 11 x$ $y= (12x-2)^2 + 11x$ ?