What is the standard form of $y= (2x-1)(3x+4)(2x+5)$ ?

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Answer 1 · 2015-11-29T00:13:15

$y=12x^3+40x^2+17x-20$

A cubic function can be expressed in standard form as:

$y=ax^3+bx^2+cx+d$

To write the equation in standard form, we have to expand the brackets:

$y=(2x-1)(3x+4)(2x+5)$
$y=(6x^2+8x-3x-4)(2x+5)$
$y=(6x^2+5x-4)(2x+5)$
$y=(12x^3+30x^2+10x^2+25x-8x-20)$
$y=12x^3+40x^2+17x-20$

What is the standard form of y= (2x-1)(3x+4)(2x+5) y= (2x-1)(3x+4)(2x+5)?