Question

What is the standard form of `y= (-2x-15)(3x-1)`?

Answer 1

See a solution process below:

Explanation:

To transform this equation to standard form you can multiply these two terms by multiplying each individual term in the left parenthesis by each individual term in the right parenthesis.

`y = (color(red)(-2x) - color(red)(15))(color(blue)(3x) - color(blue)(1))` becomes:

`y = (color(red)(-2x) xx color(blue)(3x)) + (color(red)(2x) xx color(blue)(1)) - (color(red)(15) xx color(blue)(3x)) + (color(red)(15) xx color(blue)(1))`

`y = -6x^2 + 2x - 45x + 15`

We can now combine like terms:

`y = -6x^2 + (2 - 45)x + 15`

`y = -6x^2 + (-43)x + 15`

`y = -6x^2 - 43x + 15`