What is the standard form of $y= (2x^2 -1)(6x+8)$ ?

Question

1433 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-21T10:36:34

$y= 12x^3 + 16x^2 -6x -8$

$y= 2x^2 (6x+8) -1 (6x+8)$

$y= 12x^3 + 16x^2 -6x -8$ is in standard form.

What is the standard form of y= (2x^2 -1)(6x+8) y= (2x^2 -1)(6x+8) ?