What is the standard form of #y= (2x^2 -1)(6x+8) #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Ratnesh Bhosale Jan 21, 2016 #y= 12x^3 + 16x^2 -6x -8# Explanation: #y= 2x^2 (6x+8) -1 (6x+8)# #y= 12x^3 + 16x^2 -6x -8# is in standard form. Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1280 views around the world You can reuse this answer Creative Commons License