# What is the standard form of y= (2x^2 -1)(x/4 + 5) ?

$y = {x}^{3} / 2 + 10 {x}^{2} - \frac{x}{4} - 5$
$\implies y = \frac{2}{4} {x}^{3} + 10 {x}^{2} - \frac{x}{4} - 5$
$y = {x}^{3} / 2 + 10 {x}^{2} - \frac{x}{4} - 5$