What is the standard form of $y = (2 x - 2) (3 x - 14) - 3$ $y= (2x-2)(3x-14)-3$ ?

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Answer 1 · 2015-12-24T13:33:36

$y = 6 x^{2} - 34 x + 25$ $y=6x^2-34x+25$

Distribute (FOIL) the two binomials.

$y = (6 x^{2} - 28 x - 6 x + 28) - 3$ $y=(6x^2-28x-6x+28)-3$

Combine like terms.

$y = 6 x^{2} + (- 28 x - 6 x) + (28 - 3)$ $y=6x^2+(-28x-6x)+(28-3)$

$y = 6 x^{2} - 34 x + 25$ $y=6x^2-34x+25$

This is in standard form since the degrees are placed in descending order. ( $x^{2}, x$ $x^2,x$ , constant)

What is the standard form of y=(2x−2)(3x−14)−3y= (2x-2)(3x-14)-3?