What is the standard form of $y = (2 x - 3) (2 x + 4) + {(4 x - 3)}^{2}$ $y= (2x-3)(2x+4)+(4x-3)^2$ ?

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What is the standard form of $y = (2 x - 3) (2 x + 4) + {(4 x - 3)}^{2}$ $y= (2x-3)(2x+4)+(4x-3)^2$ ?

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Answer 1 · 2015-12-23T03:04:17

$y = 20 x^{2} - 22 x - 3$ $y=20x^2 -22x -3$

Explanation:

$y = (2 x - 3) (2 x + 4) + {(4 x - 3)}^{2}$ $y= (2x-3)(2x+4)+(4x-3)^2$
by distributive property and using special product
$y = 4 x^{2} + 8 x - 6 x - 12 + 16 x^{2} - 24 x + 9$ $y = 4x^2+8x-6x-12 + 16x^2 -24x +9$
$y = 20 x^{2} - 22 x - 3$ $y=20x^2 -22x -3$

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What is the standard form of $y = (2 x - 3) (2 x + 4) + {(4 x - 3)}^{2}$ $y= (2x-3)(2x+4)+(4x-3)^2$ ?

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Explanation:

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What is the standard form of y=(2x−3)(2x+4)+(4x−3)2 y= (2x-3)(2x+4)+(4x-3)^2?

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Explanation:

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What is the standard form of $y = (2 x - 3) (2 x + 4) + {(4 x - 3)}^{2}$ $y= (2x-3)(2x+4)+(4x-3)^2$ ?