What is the standard form of $y = (2 x + 3) (3 x - 6)$ $y=(2x + 3)(3x-6)$ ?

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What is the standard form of $y = (2 x + 3) (3 x - 6)$ $y=(2x + 3)(3x-6)$ ?

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Answer 1 · 2018-03-11T08:53:33

$y = 6 x^{2} - 3 x - 18$ $y=6x^2-3x-18$

Explanation:

Standard form = Exponents in descending order.

First, expand the brackets using FOIL. See: How do you FOIL ${(7 - a)}^{2}$ $(7-a)^2$ ? for more info.

$y = (2 x \cdot 3 x) + (2 x \cdot - 6) + (3 \cdot 3 x) + (3 \cdot - 6)$ $y=(2x*3x)+(2x*-6)+(3*3x)+(3*-6)$
$y = 6 x^{2} - 12 x + 9 x - 18$ $y=6x^2-12x+9x-18$
$y = 6 x^{2} - 3 x - 18$ $y=6x^2-3x-18$

That is already in standard form/descending order.

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What is the standard form of $y = (2 x + 3) (3 x - 6)$ $y=(2x + 3)(3x-6)$ ?

1 Answer

Explanation:

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Science

Math

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What is the standard form of y=(2x+3)(3x−6)y=(2x + 3)(3x-6) ?

1 Answer

Explanation:

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What is the standard form of $y = (2 x + 3) (3 x - 6)$ $y=(2x + 3)(3x-6)$ ?