# What is the standard form of y= (2x-3)(4x-4)^2 ?

$y = 32 {x}^{3} - 112 {x}^{2} + 128 x - 48$
$y = \left(2 x - 3\right) \left(4 x - 4\right) \left(4 x - 4\right)$
$y = \left(8 {x}^{2} - 8 x - 12 x + 12\right) \left(4 x - 4\right)$
$y = \left(8 {x}^{2} - 20 x + 12\right) \left(4 x - 4\right)$
$y = 32 {x}^{3} - 80 {x}^{2} + 48 x - 32 {x}^{2} + 80 x - 48$
$y = 32 {x}^{3} - 112 {x}^{2} + 128 x - 48$