# What is the standard form of  y= (2x-3)(x+7)(-3x-2)?

Jul 8, 2017

$y = - 6 {x}^{3} - 37 {x}^{2} + 41 x + 42$

#### Explanation:

Multiply the first two expressions using the FOIL method.
$\left(2 x - 3\right) \left(x + 7\right)$
$2 {x}^{2} + 14 x - 3 x - 21$ ---> combine like terms
$2 {x}^{2} + 11 x - 21$

Here is what you have now: $y = \left(2 {x}^{2} + 11 x - 21\right) \left(- 3 x - 2\right)$

Using the same method as before, multiply the expressions together.
$\left(2 {x}^{2} + 11 x - 21\right) \left(- 3 x - 2\right)$
$- 6 {x}^{3} - 33 {x}^{2} + 63 x - 4 {x}^{2} - 22 x + 42$ ---> combine like terms
$- 6 {x}^{3} - 37 {x}^{2} + 41 x + 42$

Your final answer is $y = - 6 {x}^{3} - 37 {x}^{2} + 41 x + 42$.

I hope this helps a lot! :)