What is the standard form of $y = (2 x - 5) {(x - 1)}^{2}$ $y= (2x-5)(x-1)^2$ ?

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What is the standard form of $y = (2 x - 5) {(x - 1)}^{2}$ $y= (2x-5)(x-1)^2$ ?

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Answer 1 · 2015-12-16T07:04:06

$y = 2 x^{3} - 9 x^{2} + 12 x - 5$ $y=2x^3-9x^2+12x-5$

Explanation:

To find the standard form of the equation, expand the brackets:

$y = (2 x - 5) {(x - 1)}^{2}$ $y=(2x-5)(x-1)^2$
$y = (2 x - 5) (x^{2} - 2 x + 1)$ $y=(2x-5)(x^2-2x+1)$
$y = (2 x^{3} - 4 x^{2} + 2 x - 5 x^{2} + 10 x - 5)$ $y=(2x^3-4x^2+2x-5x^2+10x-5)$
$y = 2 x^{3} - 9 x^{2} + 12 x - 5$ $y=2x^3-9x^2+12x-5$

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What is the standard form of $y = (2 x - 5) {(x - 1)}^{2}$ $y= (2x-5)(x-1)^2$ ?

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What is the standard form of y= (2x-5)(x-1)^2 y=(2x−5)(x−1)2y= (2x-5)(x-1)^2 ?

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What is the standard form of $y = (2 x - 5) {(x - 1)}^{2}$ $y= (2x-5)(x-1)^2$ ?