What is the standard form of y= (-2x-9)^3-(3x+2)^2?

1 Answer
May 2, 2017

y=-8x^3-117x^2-498x-733

Explanation:

standard form: Ax + By = C

start by expanding each parenthesis:

(-2x-9)^3 = -8x^3-108x^2-486x-729

&

(3x+2)^2=9x^2+12x+4

subtract each set of equations:

y=(-8x^3-108x^2-486x-729)-(9x^2+12x+4)

→ y=-8x^3-117x^2-498x-733