What is the standard form of #y= (3/2x-4)^2+1#?
1 Answer
Jul 14, 2018
Explanation:
#"the standard form of a quadratic is ";ax^2+bx+c;a!=0#
#"to obtain this form expand and collect like terms"#
#y=(3/2x-4)(3/2x-4)+1#
#color(white)(y)=9/4x^2-6x-6x+16+1#
#color(white)(y)=9/4x^2-12x+17larrcolor(red)"in standard form"#
