# What is the standard form of y= (3/5x^2-1/2)(1/6x+7/8) ?

Jan 3, 2016

$y = \frac{1}{10} {x}^{3} + \frac{21}{40} {x}^{2} - \frac{1}{12} x - \frac{7}{16}$

#### Explanation:

Distribute using the FOIL method.

$y = {\overbrace{\frac{3}{5} {x}^{2} \left(\frac{1}{6} x\right)}}^{\text{first")+overbrace(3/5x^2(7/8))^("outside")+overbrace(-1/2(1/6x))^("inside")+overbrace(-1/2(7/8))^("last}}$

Multiply the fractions.

$y = \frac{1}{10} {x}^{3} + \frac{21}{40} {x}^{2} - \frac{1}{12} x - \frac{7}{16}$

This is in standard form since the degree of the each term is lower than the previous .