Question

What is the standard form of `y=-3(x-1)^2-1`?

Answer 1

Standard form is given in the form,

`y = ax^2 + bx + c`

Explanation:

So all you have to do is solve through the equation!

`y = -3(x^2-2x+1)-1`

`y = -3x^2+6x-3-1`

`y = -3x^2+6x-4`