What is the standard form of #y= (3x^2-1)(2x-7) + (4x+1)^2#?

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Answer 1 · 2018-07-10T00:08:15

#y=6x^3-5x^2+6x+8#

Given:

#y=(3x^2-1)(2x-7)+(4x+1)^2#

Expand.

#y=6x^3-21x^2-2x+7+(4x+1)^2#

Expand.

#y=6x^3-21x^2-2x+7+16x^2+8x+1#

Collect like terms.

#y=6x^3+(-21x^2+16x^2)+(-2x+8x)+(7+1)#

Combine like terms.

#y=6x^3-5x^2+6x+8#