What is the standard form of $y= (3x-4)^2+(8x-2)^2$ ?

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Answer 1 · 2016-01-04T09:10:25

$73x^2 - 56x + 20$

standard form means expanding the brackets and collecting like terms in descending order.

$(3x -4 )^2 + (8x - 2 )^2$

$= (3x - 4 )(3x - 4 ) + (8x - 2 )(8x - 2 )$

$= 3x(3x - 4 ) -4(3x - 4 ) + 8x(8x - 2 ) -2(8x - 2 )$

$= 9x^2 - 12x - 12x + 16 + 64x^2 - 16x -16x + 4$

$= 9x^2 + 64x^2 -12x - 12x -16x - 16x + 16 + 4$

$= 73x^2 - 56x + 20$

What is the standard form of y= (3x-4)^2+(8x-2)^2 y= (3x-4)^2+(8x-2)^2 ?