# What is the standard form of y= (3x-4)^2+(8x-2)^2 ?

Jan 4, 2016

$73 {x}^{2} - 56 x + 20$

#### Explanation:

standard form means expanding the brackets and collecting like terms in descending order.

${\left(3 x - 4\right)}^{2} + {\left(8 x - 2\right)}^{2}$

$= \left(3 x - 4\right) \left(3 x - 4\right) + \left(8 x - 2\right) \left(8 x - 2\right)$

$= 3 x \left(3 x - 4\right) - 4 \left(3 x - 4\right) + 8 x \left(8 x - 2\right) - 2 \left(8 x - 2\right)$

$= 9 {x}^{2} - 12 x - 12 x + 16 + 64 {x}^{2} - 16 x - 16 x + 4$

$= 9 {x}^{2} + 64 {x}^{2} - 12 x - 12 x - 16 x - 16 x + 16 + 4$

$= 73 {x}^{2} - 56 x + 20$