# What is the standard form of  y= 3x(x-3)+(2-x)(x-4/5) ?

Jan 23, 2016

$10 {x}^{2} - 31 x - 5 y - 8 = 0$

#### Explanation:

$y = 3 x \left(x - 3\right) + \left(2 - x\right) \left(x - \frac{4}{5}\right)$

Use the distributive property

$y = 3 {x}^{2} - 9 x + 2 x - \frac{8}{5} - {x}^{2} + \frac{4 x}{5}$

$y = 2 {x}^{2} - \frac{31}{5} x - \frac{8}{5}$

Then multiply the whole equation with 5

$\left(y = 2 {x}^{2} - \frac{31}{5} x - \frac{8}{5}\right) \cdot 5$

$5 y = 10 {x}^{2} - 31 x - 8$

$5 y - 10 {x}^{2} + 31 x + 8 = 0$

$10 {x}^{2} - 31 x - 5 y - 8 = 0$ And this is the final standard answer