What is the standard form of $y= 4(x-5)^3 + 1$ ?

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Answer 1 · 2017-03-06T01:48:54

$4x^3-y-61=0$

Standard form is $Ax+By+C=0$

Using PEMDAS,

$y=4(x^3-15)+1$

$y=4x^3-60+1$

$y=4x^3-61$

$y-y=4x^3-61-y$

$4x^3-y-61=0$

What is the standard form of y= 4(x-5)^3 + 1 y= 4(x-5)^3 + 1 ?