What is the standard form of y=(4x + 3)(x/2-5) y=(4x+3)(x2−5)?

1 Answer
Patrick H.
Jun 23, 2018

y=2x^2-37/2x-15y=2x2−372x−15

Explanation:

Let's use FOIL to simplify this problem and get rid of the parentheses:

y=(4x+3)(x/2-5)y=(4x+3)(x2−5)
y=(4x)(x/2)+(4x)(-5)+(3)(x/2)+(3)(-5)y=(4x)(x2)+(4x)(−5)+(3)(x2)+(3)(−5)
y=(4x^2)/2+(-20x)+3/2x+(-15)y=4x22+(−20x)+32x+(−15)
y=2x^2-20x+3/2x-15y=2x2−20x+32x−15
y=2x^2-37/2x-15y=2x2−372x−15

Since we are in standard form (terms are in descending order based on their degrees), this is our answer.

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