What is the standard form of # y= (-4x+4)^3-(5x+12)^2#?

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Answer 1 · 2018-03-11T05:30:42

#y=-64x^3+167x^2-312x-80#

The standard form of a cubic function is :

#y=ax^3+bx^2+cx+d#

Therefore after expanding

#(-4x-4)^3 #

= #-64x^3+192x^2-192x+64#

and

#(5x+12)^2 #

= #25x^2+120x+144#

We can join the 2 expressions

#y=(-64x^3+192x^2-192x+64) - (25x^2+120x+144)#

#y=-64x^3+167x^2-312x-80#