# What is the standard form of y-4x= -(x-1)^2+x^3?

$y - 4 x = - {\left(x - 1\right)}^{2} + {x}^{3}$
$y = - \left({x}^{2} - 2 x + 1\right) + {x}^{3} + 4 x$
$y = - {x}^{2} + 2 x - 1 + {x}^{3} + 4 x$
$y = {x}^{3} - {x}^{2} + 6 x - 1$