What is the standard form of $y - 4 x = - {(x - 1)}^{2} + x^{3}$ $y-4x= -(x-1)^2+x^3$ ?

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What is the standard form of $y - 4 x = - {(x - 1)}^{2} + x^{3}$ $y-4x= -(x-1)^2+x^3$ ?

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Answer 1 · 2016-11-07T05:26:42

$y - 4 x = - {(x - 1)}^{2} + x^{3}$ $y-4x=-(x-1)^2+x^3$
$y = - (x^{2} - 2 x + 1) + x^{3} + 4 x$ $y=-(x^2-2x+1)+x^3+4x$
$y = - x^{2} + 2 x - 1 + x^{3} + 4 x$ $y=-x^2+2x-1+x^3+4x$
$y = x^{3} - x^{2} + 6 x - 1$ $y=x^3-x^2+6x-1$

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What is the standard form of $y - 4 x = - {(x - 1)}^{2} + x^{3}$ $y-4x= -(x-1)^2+x^3$ ?

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What is the standard form of $y - 4 x = - {(x - 1)}^{2} + x^{3}$ $y-4x= -(x-1)^2+x^3$ ?