What is the standard form of $y = (4 x + x^{2}) (x - 7) - {(2 x + 3)}^{2}$ $y= (4x+x^2)(x-7) -(2x+3)^2$ ?

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What is the standard form of $y = (4 x + x^{2}) (x - 7) - {(2 x + 3)}^{2}$ $y= (4x+x^2)(x-7) -(2x+3)^2$ ?

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Answer 1 · 2018-06-03T15:50:08

$y = x^{3} - 7 x^{2} - 40 x - 9$ $y=x^3-7x^2-40x-9$

Explanation:

Multiplying out:
$y = 4 x^{2} + x^{3} - 28 x - 7 x^{2} - (4 x^{2} + 9 + 12 x)$ $y=4x^2+x^3-28x-7x^2-(4x^2+9+12x)$
so we get

$y = 4 x^{2} + x^{3} - 28 x - 7 x^{2} - 4 x^{2} - 9 - 12 x$ $y=4x^2+x^3-28x-7x^2-4x^2-9-12x$
Combining likewise terms
$y = x^{3} - 7 x^{2} - 40 x - 9$ $y=x^3-7x^2-40x-9$

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What is the standard form of $y = (4 x + x^{2}) (x - 7) - {(2 x + 3)}^{2}$ $y= (4x+x^2)(x-7) -(2x+3)^2$ ?

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Explanation:

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What is the standard form of $y = (4 x + x^{2}) (x - 7) - {(2 x + 3)}^{2}$ $y= (4x+x^2)(x-7) -(2x+3)^2$ ?