What is the standard form of $y=5(x-3)^2-7$ ?

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Answer 1 · 2016-01-27T07:41:21

$y = 5x^2 - 30x + 38$

Since this is a quadratic equation, the standard form should appear this way

$y = ax^2 + bx + c$

In this case, you will have to expand and simplify (if possible) the equation to get the standard form.

[Solution]
$y = 5(x - 3)^2 - 7$
$y = 5(x^2 - 6x + 9) - 7$
$y = 5x^2 - 30x + 45 - 7$
$y = 5x^2 - 30x + 38$

What is the standard form of y=5(x-3)^2-7y=5(x-3)^2-7?