What is the standard form of $y = (5 x - 9) (3 x + 4) + {(x - 3)}^{2}$ $y= (5x-9)(3x+4)+(x-3)^2$ ?

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What is the standard form of $y = (5 x - 9) (3 x + 4) + {(x - 3)}^{2}$ $y= (5x-9)(3x+4)+(x-3)^2$ ?

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Answer 1 · 2016-02-23T21:26:40

$16 x^{2} - 13 x - 27$ $16x^2 - 13x - 27$

Explanation:

Distribute each 'pair' of brackets using FOIL , or any method you have for multiplying brackets.

{(5x - 9 )(3x + 4 )] + [ (x - 3 )(x - 3 ) ]

$= 15 x^{2} + 20 x - 27 x - 36 + x^{2} - 3 x - 3 x + 9$ $=15x^2+20x-27x-36 + x^2-3x-3x+9$

'collect like terms' , starting with the highest power terms and decreasing.

$= 16 x^{2} - 13 x - 27$ $= 16x^2 - 13x - 27$

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What is the standard form of $y = (5 x - 9) (3 x + 4) + {(x - 3)}^{2}$ $y= (5x-9)(3x+4)+(x-3)^2$ ?

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What is the standard form of y=(5x−9)(3x+4)+(x−3)2 y= (5x-9)(3x+4)+(x-3)^2?

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What is the standard form of $y = (5 x - 9) (3 x + 4) + {(x - 3)}^{2}$ $y= (5x-9)(3x+4)+(x-3)^2$ ?