What is the standard form of # y= (6x-7)(6x-2)(1/6x-1/49)#?

1 Answer
Tony B
Jun 19, 2016

I got: #y=6x^3 -447/49x^2+505/147x-2/7#

Explanation:

#color(blue)("Multiply the last 2 brackets because "6/6 x=x)#
Consider:#" "(6x-2)(1/6x-1/49)#

=#x^2-6/49x-2/6x +2/49" " =" "x^2-67/147x+2/49 #

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Multiply by the first bracket")#

#=(6x-7)(x^2-67/147x+2/49) #

#=6x^3-134/49x^2 +12/49x" "-7x^2+67/21x-2/7#

#=6x^3 -447/49x^2+505/147x-2/7#

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