What is the standard form of y=7(x-3)^2+4?

Nov 23, 2016

$y = 7 {x}^{2} - 42 x + 67$

Explanation:

First, cross multiply the term in parenthesis:

$y = 7 \left({x}^{2} - 3 x - 3 x + 9\right) + 4 \implies y = 7 \left({x}^{2} - 6 x + 9\right) + 4$

Next expand the term in parenthesis:

$y = 7 \left({x}^{2} - 6 x + 9\right) + 4 \implies y = 7 {x}^{2} - 42 x + 63 + 4$

Finally, combine like terms:

$y = 7 {x}^{2} - 42 x + 63 + 4 \implies y = 7 {x}^{2} - 42 x + 67$