What is the standard form of #y=7(x-3)^2+4#?

1 Answer
smendyka
Nov 23, 2016

#y = 7x^2 - 42x + 67#

Explanation:

First, cross multiply the term in parenthesis:

#y = 7(x^2 - 3x - 3x + 9) + 4 => y = 7(x^2 - 6x + 9) + 4#

Next expand the term in parenthesis:

#y = 7(x^2 - 6x + 9) + 4 => y = 7x^2 - 42x + 63 + 4#

Finally, combine like terms:

#y = 7x^2 - 42x + 63 + 4 => y = 7x^2 - 42x + 67#

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