What is the standard form of $y=7(x-3)^2+4$ ?

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Answer 1 · 2016-11-23T13:37:30

$y = 7x^2 - 42x + 67$

First, cross multiply the term in parenthesis:

$y = 7(x^2 - 3x - 3x + 9) + 4 => y = 7(x^2 - 6x + 9) + 4$

Next expand the term in parenthesis:

$y = 7(x^2 - 6x + 9) + 4 => y = 7x^2 - 42x + 63 + 4$

Finally, combine like terms:

$y = 7x^2 - 42x + 63 + 4 => y = 7x^2 - 42x + 67$

What is the standard form of y=7(x-3)^2+4y=7(x-3)^2+4?