What is the standard form of $y=8(x^2 - 16) (x^2 -16)(x^3 + 8)$ ?

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Answer 1 · 2018-05-31T05:54:34

$color(crimson)(y = 8x^7 - 256x^5 + 64x^4 + 2048x^3 - 2048x^2 + 16394$

$y = 8(x^2 - 16) (x^2-16)(x^3+8)$

$y = 8 (x^4 - 32x^2 + 256)(x^3+8)$

$y = 8 (x^7 - 32x^5 + 256x^3 + 8x^4 - 256x^2 + 2048)$

$color(crimson)(y = 8x^7 - 256x^5 + 64x^4 + 2048x^3 - 2048x^2 + 16394$

What is the standard form of y=8(x^2 - 16) (x^2 -16)(x^3 + 8) y=8(x^2 - 16) (x^2 -16)(x^3 + 8) ?