What is the standard form of y= (9x-2)(x+2)(7x-4)y=(9x−2)(x+2)(7x−4)?

1 Answer
Ridinion K.
Jun 10, 2018

y=63x^3-148x^2+50x+8y=63x3−148x2+50x+8

Explanation:

The standard form refers to the format of an expression where the terms are arranged in a descending order. The degree is determined by the exponent value of the variable of each term.

To find the standard form, multiply the brackets out and simplify.

y=(9x-2)(x+2)(7x-4)y=(9x−2)(x+2)(7x−4)

Lets multiply out y=(9x-2)(x+2)y=(9x−2)(x+2) first:

y=(9x-2)(x+2)y=(9x−2)(x+2)
y=9x^2+18x-2x-2y=9x2+18x−2x−2
y=9x^2-16x-2y=9x2−16x−2

Then multiply y=(9x^2-16x-2)(7x-4)y=(9x2−16x−2)(7x−4):

y=(9x^2-16x-2)(7x-4)y=(9x2−16x−2)(7x−4)
y=63x^3-36x^2-112x^2+64x-14x+8y=63x3−36x2−112x2+64x−14x+8
y=63x^3-148x^2+50x+8y=63x3−148x2+50x+8

This is the standard form.

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