What is the standard form of # y= (x-1)^2+2x #?

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Answer 1 · 2018-03-25T20:19:05

#y=x^2+1#

We have #y=(x-1)^2+2x#

First expand:

#y=(x^2-2x+1)+2x#

Then combine similar terms:

#y=x^2+(2x-2x)+1#

#y=x^2+1#

Remember to write all terms in order of decreasing degree (decreasing powers of #x#).