# What is the standard form of y=(-x - 1) (3x - 2) (4x + 1) ?

Feb 3, 2016

$y = \left(- x - 1\right) \left(3 x - 2\right) \left(4 x + 1\right)$

First multiply the two binomials using FOIL method:

$\underline{F}$irsts
$\underline{O}$utsides
$\underline{I}$nsides
$\underline{L}$asts

So,

$\rightarrow \left(- x - 1\right) \left(3 x - 2\right) = - 3 {x}^{2} + 2 x - 3 x + 2 = \left(- 3 {x}^{2} - x + 2\right)$

Now multiply:

$\left(- 3 {x}^{2} - x + 2\right) \left(4 x + 1\right)$

Use the distributive law and multiply:

$\rightarrow y = - 12 {x}^{3} - 7 {x}^{2} + 7 x + 2$