What is the standard form of  y= (-x+1)(-3x-2)(6x-1)?

$y = 18 {x}^{3} - 9 {x}^{2} - 11 x + 2$

Explanation:

The given seems like the factored form
$y = \left(- x + 1\right) \left(- 3 x - 2\right) \left(6 x - 1\right)$

For what I know, standard form is that kind of arrangement of the terms from highest degree to the lowest degree term after multiplying all these factors.

$y = \left(- x + 1\right) \left(- 3 x - 2\right) \left(6 x - 1\right)$

multiply the first two factors
$y = \left(3 {x}^{2} + 2 x - 3 x - 2\right) \left(6 x - 1\right)$
simplify by combining similar terms
$y = \left(3 {x}^{2} - x - 2\right) \left(6 x - 1\right)$
multiply the remaining factors
$y = 18 {x}^{3} - 6 {x}^{2} - 12 x - 3 {x}^{2} + x + 2$
simplify again to obtain the final answer. Make sure the terms are arranged from highest to lowest degree
$y = 18 {x}^{3} - 9 {x}^{2} - 11 x + 2$

God bless....I hope the explanation is useful.