What is the standard form of #y=-(x - 1) (x^2 +6)(x/3 + 2) #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Hihi Feb 24, 2018 #y=-1/3x^4-5/3x^3-10x+12# Explanation: #y=-(x-1)(x^2+6)(x/3+2)# #y=-(x^3+6x-x^2-6)(1/3)(x+6)# #y=-1/3(x^3-x^2+6x-6)(x+6)# #y=-1/3(x^4-x^3+6x^2-6x+6x^3-6x^2+36x-36)# #y=-1/3(x^4+5x^3+30x-36)# #y=-1/3x^4-5/3x^3-10x+12# Which fits the standard form of #y=Ax^4+Bx^3+Cx^2+Dx+E# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1438 views around the world You can reuse this answer Creative Commons License